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ADP5072ACBZ-R7 Datasheet(PDF) 20 Page - Analog Devices |
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ADP5072ACBZ-R7 Datasheet(HTML) 20 Page - Analog Devices |
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20 / 24 page ![]() ADP5072 Data Sheet Rev. 0 | Page 20 of 24 Inverting Regulator The inverting converter, like the boost converter, produces an undesirable right half plane zero in the regulation feedback loop. This feedback loop requires compensating the regulator such that the crossover frequency occurs well below the frequency of the right half plane zero. The right half plane zero frequency is determined by the following equation: (1 ) 2 2 LOAD2 2 Z2 2 R DUTY f (RHP) π L2 DUTY − = ×× where: fZ2(RHP) is the right half plane zero frequency. RLOAD2 is the equivalent load resistance or the output voltage divided by the load current. NEG DIODE2 2 IN NEG DIODE2 |V | V DUTY V |V | V + = ++ where VDIODE2 is the forward voltage drop of the Schottky diode (D2). To stabilize the regulator, ensure that the regulator crossover frequency is less than or equal to one-tenth of the right half plane zero frequency. The inverting regulator loop gain is ( 2 | |) FB2 IN VL2 M2 NEG IN NEG OUT2 COMP2 CS2 OUT2 VV Ag |V | V V R ||Z g Z = × ×× + × ×× where: AVL2 is the loop gain. VFB2 is the feedback regulation voltage. VNEG is the regulated negative output voltage. VIN is the input voltage. gM2 is the error amplifier transconductance gain. ROUT2 is the output impedance of the error amplifier and is 33 MΩ. ZCOMP2 is the impedance of the series RC network from COMP2 to AGND. gCS2 is the current sense transconductance gain (the inductor current divided by the voltage at COMP2), which is internally set by the ADP5072 and is 6.25 A/V. ZOUT2 is the impedance of the load in parallel with the output capacitor. To determine the crossover frequency, it is important to note that, at that frequency, the compensation impedance (ZCOMP2) is dominated by a resistor, RC2, and the output impedance (ZOUT2) is dominated by the impedance of the output capacitor, COUT2. Therefore, when solving for the crossover frequency, the equation (by definition of the crossover frequency) is simplified to ( 2 | |) 1 1 2 FB2 IN VL2 M2 NEG IN NEG C2 CS2 C2 OUT2 VV Ag |V | V V Rg πf C = × × × + × × × = × × where fC2 is the crossover frequency. To solve for RC2, use the following equation: 2 (2 | |) C2 OUT2 NEG IN NEG C2 FB2 IN M2 CS2 π f C |V | (V V R V Vg g × × × × +× = × × × where GCS2 = 6.25 A/V. Using typical values for VFB2 and GM2 results in 2 4188 | | ( (2 | |) C2 OUT NEG IN NEG C2 IN fC V V V R V × × × × +× = For improved accuracy, it is recommended to use the value of the output capacitance, COUT2, expected for the dc bias conditions under which it operates in the calculation for RC2. After the compensation resistor is known, set the zero formed by the compensation capacitor and resistor, CC2 and RC2, to one- fourth of the crossover frequency, or 2 C2 C2 C2 C πf R = × × where CC2 is the compensation capacitor. ERROR AMPLIFIER REF2 gM2 FB2 COMP2 RC2 CC2 Figure 45. Compensation Component |
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